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Numerical
The sides of a right-angled triangle containing the right angle are 5x and 3x-1. If the area of the triangle is 60 cm2, find the sides of the triangle.
Solution:
Given: Area of triangle 60 cm2
1 by 2 *3x-1 *5x = 60
Therefore 15x2 - 5x - 120 = 0
Solving the equation 3x2 - x - 24 = 0 we get x = -8 by 3 and x = 3
Since the length of the side of the triangle cannot be negative discard the negative value x = -8 by 3 hence x = 3.
Taking the value X = 3 and find the values of the sides of the triangle
From triangle ABC we have AC2 = AB2 + BC2
Key in the values for the sides AB and BC and find the values of AC.
Hence, the sides of the triangle are 15 cm,8 cm and 17 cm.
Numerical
The sides of a right-angled triangle containing the right angle are 5x and 3x-1. If the area of the triangle is 60 cm2, find the sides of the triangle.
Solution:
Given: Area of triangle 60 cm2
1 by 2 *3x-1 *5x = 60
Therefore 15x2 - 5x - 120 = 0
Solving the equation 3x2 - x - 24 = 0 we get x = -8 by 3 and x = 3
Since the length of the side of the triangle cannot be negative discard the negative value x = -8 by 3 hence x = 3.
Taking the value X = 3 and find the values of the sides of the triangle
From triangle ABC we have AC2 = AB2 + BC2
Key in the values for the sides AB and BC and find the values of AC.
Hence, the sides of the triangle are 15 cm,8 cm and 17 cm.
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